2a^2=(11.3)^2

Solution for 2a^2=(11.3)^2 equation:

2a^2=(11.3)^2

We move all terms to the left:

2a^2-((11.3)^2)=0

We add all the numbers together, and all the variables

2a^2-127.69=0

a = 2; b = 0; c = -127.69;
Δ = b2-4ac
Δ = 02-4·2·(-127.69)
Δ = 1021.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1021.52}}{2*2}=\frac{0-\sqrt{1021.52}}{4}
=-\frac{\sqrt{}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1021.52}}{2*2}=\frac{0+\sqrt{1021.52}}{4}
=\frac{\sqrt{}}{4}
$